I'm given f(x) = x^2 + 2x - 1 and need to find the inverse. I have gotten this far
2. Solve the equation and check the proposed solutions 2/x+2/x+1 = 3x-1/x^2-1. Show all work.
Находим значение данной функции в точке х=1, получаем: f (x0)=f (1) = 1. Найдем производную данной функции по формуле производной степени
For functions, the two notations mean the exact same thing, but "f(x)" gives you more flexibility and more information. You used to say "y = 2x + 3; solve for y when x = –1". Now you say "f(x) = 2x + 3; find f(–1)" (pronounced as "f-of-x is 2x plus three; find f-of-negative-one").
Simple and best practice solution for f(x)=-x^2-2x-1 equation. Check how easy it is, and learn it for the future. Our solution is simple, and easy to understand, so don`t hesitate to use it as a solution of your homework.
4. f(x)=sin^2( x)*e^(2x) Используем фррмулу (uv)' =u'v+v'u f ’(x)=(sin^2(x)’*e^(2x)+sin^2(x)*(e^(2x))’ = =2sin(x)*cos(x)*e^(2x)+2e^2(x)*sin^2(x) 5. f(x)=e^xsinx [/tex] Не понятно, что такое [/тех]?
Updated: If you are saying (x)=(x^2 - 2)/(x-1) [please update your equation with brackets and powers if this is incorrect] to determine the instantaneous rate of change, we need to calculate the derivative, and then substitute our value of x=2 to obtain the instantantaneous rate of change.
f'(x) Найти производную функции онлайн. Помимо производной вы увидете на сравнение графика функции и графика производной функции.
Im having some trouble understanding Big-O estimates. Im using Discrete Mathematics And Its Applications by Rosen 6th Edition. In section 3.2 one of the example problems says to show that f(x) - x^2 + 2x + 1 is O(x^2).
This means we have to find the sign of the function between zeros and apply the definition of absolute value. As you noted, there are zeros at 0 and 2; these are the only two zeros of $x^2-2x$. We can check signs between and outside these points to find that. $x^2-2x>0$ if $x>2$ or $x<0$. $x...