Detailed step by step solution for x^4-8x^3+24x^2-32x+16=0.

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Exponent, a small number x^4-8x^3+24x^2-32x+16 written above and to the right of the base number, tells how many times the base number is being multiplied ...

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22 февр. 2021 г. ... x = -2 + (3)^1/2 i. x + 2 = i (3)^1/2. (x + 2)^4 = 9. Expanding the L.H.S gives,. x^4 + 8x^3 + 24x^2 + 32x + 16 = 9. Thus the answer is 9.

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. I saw those factors immediately. One process is to note that 16. has divisors, and one can try various combinations of this such that the sum gives eight. Possibilities include 2,2,2,2. First, factor out the polynomial. x4−2x3−6x3+12x2+12x2−24x−8x+16=0.

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Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, ...

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Solve your math problems using our free math solver with step-by-step solutions. Our math solver supports basic math, pre-algebra, algebra, trigonometry, ...

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15 окт. 2017 г. ... x4 + 4x3 + 6x2 + 4x + 1 8x3 + 24x2 + 32x x4 + 8x3 + 24x2 + 32x + 16 2x4 + 8x3 + 12x2 + 8x + 2. 2. See answers.

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x^4-8*x^3+24*x^2-32*x+16=0 Главная / x^4-8*x^3+24*x^2-32*x+16=0

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25 апр. 2023 г. ... The value of the binomial expansion of (x + 2)⁴ is, ⇒ x⁴ + 8x³ + 24x² + 32x + 16 We have to given that; The expression is, ⇒ (x + 2)⁴ Use ... x^4-8*x^3+24*x^2-32*x+16=0 Главная / x^4-8*x^3+24*x^2-32*x+16=0

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How do you factor #x^5 - 5x^4 - x^3 + x^2 + 4 = 0#? ... How do you factor #x^3+2x^2-8x-16? How do you factor ... How do you factor #8x^4 + 4x^3 - 24x^2 #? · How do ... x^4-8*x^3+24*x^2-32*x+16=0 Главная / x^4-8*x^3+24*x^2-32*x+16=0

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24 апр. 2023 г. ... 2. You can then use completing square method to solve the equation. x4−8x3+24x2−32x+16−16−14=0. (x−2)4−30=0. x=2±4√30 and x=2±i4√30. x^4-8*x^3+24*x^2-32*x+16=0 Главная / x^4-8*x^3+24*x^2-32*x+16=0

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30 мар. 2014 г. ... How to solve x4−8x3+24x2−32x+16=0 · 1. (x−2)4=0. · Guess a root α, then divide the equation by x−α. Repeat. · Since there are a lot of ... x^4-8*x^3+24*x^2-32*x+16=0 Главная / x^4-8*x^3+24*x^2-32*x+16=0

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