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||. 1. 8. Make the second term into an improper fraction by multiplying the 2 and the denominator (8) and adding the numerator (5). ||. ∞0 100. 87. 21. 8.

x^4-8x^3+20x^2-48x > 0

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2 & 3. 20. 1 & 20. 2 & 10. 4 & 5. 30. 1 & 30. 2 & 15. 3 & 10. 5 & 6. 8. 1 & 8. 2 & 4 ... 2 & 32. 4 & 16. 8 & 8. 39. 1 & 39. 3 & 13 ... 2 & 64. 4 & 32. 8 & 16. 119.

Решите уравнение с помощью разложения на... - ответ на Uchi.ru

Решить с помощью разложения на множители x^3+8x^2-4x-32=0

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f ( x ) = ( x – 3) 2 – 4; the minimum value is –4. ... 32x to get 3 (x+2)2 =27x in step 2. Page 85. These ... (x – 8)2 = 64. C. (x – 4)2 = 24. D. (x – 2)2 = 8. Page ...

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The because 42 = 16. ... Explanation: Although 8x3 + 4x is equal to both 2x(4x2 ... This is not a trinomial, but it can become one by adding 0x. x2 -64 = x2 +0x -64.

Simplify: x^4-8x^3+24x^2-32x+16 Tiger Algebra Solver

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Problems 58-62: Find x: 58. 4 • 9 = x. 61. 64. 3. = x. 59. x = 4. 9. 62. x = 8. 2. 3. 4. 3. 2. 60. 64. 3. = x. Problems 63-64: Write with positive exponents: 63 ...

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√32=√2 5=√2 4·2 1. =√2 4·√2. =2 2 ... 3 x 2 y 4= 3√3 3 z 2 y 3 y. = 3√3 3 y 3 3 ... Solution 4√64 x 4 y 10= 4√2 6 x 4 y 10. = 4√(2 4 ...

algebra precalculus - How to solve $x^4-8x^3+24x^2-32x+16...

How can we solve this equation? $x^4-8x^3+24x^2-32x+16=0.$ $\begingroup$ Since there are a lot of powers of two appearing in the polynomial equation, try $x=2$ and find that it is a solution.

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‍ is equivalent to log 2 ⁡ ( 48 ) = x ‍ . And just like that we have solved the equation! The exact solution is ...

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Find roots of x^3+2x^2-48x+320

The constant term is 320, with a single factor of 1, 2, 4, 5, 8, 10, 16, 20, 32, 40, 64, 80, 160 and 320. The leading coefficient is 1, with a single factor ...